The scores of four roommates on the Law School Admission Test (LSAT) are:

628 593 455 503

Find the mean, the standard deviation, and the standard error of the mean. Is it appropriate to calculate a confidence interval for these data? Explain why or why not.

Step-by-step explanation:

The given scores are 628 593 455 503

Mean = sum of scores/number of scores

Mean = (628 + 593 + 455 + 503)/4

Mean = 544.75

Standard deviation = √summation(x - mean)/n

Summation x - mean =

(628 - 544.75)^2 + (593 - 544.75)^2 + (455 - 544.75)^2 + (503 - 544.75)^2 = 19056.75

n = 4

Standard deviation = √(19056.75/4) = √4764.1875

= 60.02

The standard error of the mean = standard deviation/√n

Standard error = 60.02/√4 = 30.01

it is inappropriate to calculate a confidence interval for these data. This is because confidence interval is usually calculated for an unknown population parameter. From the data given, the population parameters are already known

the thermometer is precise but not accurate

step-by-step explanation: