You are walking around your neighborhood and you see a child on top of a roof of a building kick a soccer ball. The soccer ball is kicked at 39° from the edge of the building with an initial velocity of 17 m/s and lands 63 meters away from the wall. How tall, in meters, is the building that the child is standing on?

60.45 m

Step-by-step explanation:

The ball was kicked at 39° from the edge of the building with a velocity of 17 m/s

horizontal component of the bail's velocity vₓ₀ = v₀ cos 39° = 17 m/s cos 39° = 13.211 m/s

vertical component of the ball's velocity vy₀ = v₀ sin 39° = 10.7 m/s

horizontal distance traveled ( range ) = vₓ₀ × t

63 m = 13.211 m/s t

t = 63 m / 13.211 m/s = 4.77 s

vertical distance covered

final distance  - initial distance = vy₀t - gt²

initial distance = gt² -vy₀t = 111.49 m - ( 10.7 × 4.77) = 60.45 m