How much does each fish weigh if all the fish total weigh 240. The 1 fish weighs twice as much as the 2 fish and the 3 fish weighs twice as much as the 1 fish. The weight of the last fish weighs 5 times as much as the 2 fish

S = 20

F = 40

T = 80

L = 100

Step-by-step explanation:

Let 1st fish= F

2nd fish = S

3rd fish = T

4th fish = last fish = L

From the question,

The 1st fish weighs twice as much as the 2nd fish. I.e

F = 2S (1)

and the 3rd fish weighs twice as much as the 1st fish. I.e

T = 2F (2)

But F = 2S from (1) substitute for F

T = 2(2S)

T = 4S (3)

The weight of the last fish weighs 5 times as much as the 2nd fish. I.e

L = 5S (4)

We have,

1st + 2nd + 3rd + 4th = 240 I.e

F + S + T + L = 240 (5)

Substitute F, T and L into (5)

2S + S + 4S + 5S = 240

12S = 240

S = 20

From equation (1)

F = 2S = 40

From equation ( 3)

T = 4S = 80

From equation (4)

L = 5S = 100

answ5

step-by-step explanation:

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