In a sample of 6060 stores of a certain company, 5050 violated a scanner accuracy standard. It has been demonstrated that the conditions for a valid large-sample confidence interval for the true proportion of the stores that violate the standard were not met. Determine the number of stores that must be sampled in order to estimate the true proportion to within 0.050.05 with 9595% confidence using the large-sample method.

385

Step-by-step explanation:

Given : In a sample of 60 stores of a certain company, 50 violated a scanner accuracy standard.

Let p be the true proportion of the stores that violate the standard.

Since , it  has been demonstrated that the conditions for a valid large-sample confidence interval for p were not met.

So , to get accurate result , we take (It will give the minimum required sample size when prior information about p is not given )

Formula to find sample size : , where z= critical z-value for confidence interval and E is the margin of error

Since , E=0.05 and Critical z-value for 95% confidence=1.96

Hence, the number of stores that must be sampled= 385.

this was already solved by me with a different person. if you look it up in the search bar at the top of the page, you will get the answer.

step-by-step explanation:

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation: