JAZL
Lesson 7.4: Measures of Center
Assignment Active
Determining Frequency for a Histogram
Consider the data set shown below.
42, 43, 46, 47, 47, 48, 49, 50, 51, 53, 55, 55, 59
co
To create a histogram of the data given, identify the
frequency for the given intervals.
The interval 44-47 has a frequency of
The interval 48-51 has a frequency of
The interval 56-59 has a frequency of
Frequency
O-Nw to
40-43
44–47 '48-51
52–55
56-59
us Activity

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step-by-step explanation:

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

inverse operation of addition