The amount c in grams of a 100 gram sample of carbon-14 remaining after t years is represented by the equation c= 100 (0.99988)t use a calculator to find the amount of carbon-14 remaining after 4 years

The amount of carbon-14 remaining after 4 years is 99.95 grams.

Given that,

The amount c in grams of a 100-gram sample of carbon-14 remaining after t years is represented by the equation,

We have to determine,

The amount of carbon-14 remaining after 4 years.

According to the question,

Equation;

Where the amount c in grams of a 100-gram sample of carbon-14 remaining after t years is represented by the equation,

To determine the amount of carbon-14 remaining after 4 years following all the steps given below.

Then,

The amount of carbon-14 remaining after 4 years is,

Hence, The amount of carbon-14 remaining after 4 years is 99.95 grams.

For more details refer to the link given below.

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The amount of carbon-14 remaining after 4 years is 99.95 grams.

Step-by-step explanation:

Hi, to answer this question we simply have to substitute t=4 in the equation given and solve for c.

c= 100 (0.99988)^t

c =100 (0.99988)^4

c = 100 x 0.999520086

c= 99.95200864 ≅99.95 grams (rounded)

The amount of carbon-14 remaining after 4 years is 99.95 grams.

Feel free to ask for more if needed or if you did not understand something.

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.