A single six-sided fair die is tossed, what is the probability of obtaining a number greater than 4?

1/3 or 0.333333

Step-by-step explanation:

The question talks about a die that was tossed once and we are now asked to find the probability that it is a figure greater than 4

---A die has 6 faces with the numbers 1,2,3,4,5 and 6 one on each of

the six faces.Considering an unbaised die the probability of any of the faces to appear in a single roll is 1/6.

So, P(1)=P(2)=P(3)=P(4)=P(5)=P(6)=1/6

Now that numbers greater than 4 are 5 and 6

So it can be P(5) or P(6)= P(5)+P(6)=2/6 = 1/3 or 0.33333

Answer 1/3 or 0.33333

if the pizza is divided equally into 2 equal halves then you would get

πr^2/2

where r is the radius of the pizza.

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