Find either of the values of x
2x^2+3x-2=3

x = 1 or x = -5/2

Step-by-step explanation:

Solve for x over the real numbers:

2 x^2 + 3 x - 2 = 3

Divide both sides by 2:

x^2 + (3 x)/2 - 1 = 3/2

Add 1 to both sides:

x^2 + (3 x)/2 = 5/2

Add 9/16 to both sides:

x^2 + (3 x)/2 + 9/16 = 49/16

Write the left hand side as a square:

(x + 3/4)^2 = 49/16

Take the square root of both sides:

x + 3/4 = 7/4 or x + 3/4 = -7/4

Subtract 3/4 from both sides:

x = 1 or x + 3/4 = -7/4

Subtract 3/4 from both sides:

x = 1 or x = -5/2

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!

2160ft3

step-by-step explanation: