Refer to the accompanying data set of mean drive-through service times at dinner in seconds at two fast food restaurants. construct a 95% confidence interval estimate of the mean drive-through service time for restaurant x at dinner; then do the same for restaurant y. compare the results.

Step-by-step explanation:

Assuming the data is as shown, restaurant X has a mean service time of 180.56, with a standard deviation of 62.6.

The standard error is SE = s/√n = 62.6/√50 = 8.85.

At 95% confidence, the critical value is z = 1.960.

Therefore, the confidence interval is:

180.56 ± 1.960 × 8.85

180.56 ± 17.35

(163, 198)

Restaurant Y has a mean service time of 152.96, with a standard deviation of 49.2.

The standard error is SE = s/√n = 49.2/√50 = 6.96.

At 95% confidence, the critical value is z = 1.960.

Therefore, the confidence interval is:

152.96 ± 1.960 × 6.96

152.96 ± 13.64

(139, 167)

2x3 – 6x2 – 14x + 24 square centimeters

if i'm wrong i'm sorry : )

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i