Jose is wrapping a stack of 100 coins in a paper holder. Each coin is 1/8 inch thick and has a diameter of 1 inch. How many square inches of paper will Jose need to cover the stack of coins?

Jose will need 39.25 square inches of paper to wrap the stack of coins

Explanation:

The resulting figure of a stack of 100 coins will be a right circular cylinder. We assume that Jose wraps around the cylinder (so it means not including the bases). Therefore we are solving for the lateral surface area of the cylinder: LSA = 2πrh.

To solve for height h, we multiply the thickness of the coin 100 times.

h = 100 * 1/8 in = 12.5 inches

Solving for radius r:

r = 1 inch/2 = 0.5 inches

LSA = 2(3.14)(0.5 in)(12.5 in) = 39.25 square inches 

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068

correct answer is b. 27/8

step-by-step explanation: