Find which term in the geometric sequence 1, 3, 9, 27, ... is the first to exceed 7,000.

hint (use a table)

10th term

Step-by-step explanation:

3ⁿ⁻¹ > 7000

log₃ 7000 = 8.05

n - 1 > 8

n > 9

10th term

check: 1, 3, 9, 27, 81, 243, 729, 2187, 6561, 19683

so then what are you asking?

step-by-step explanation:

answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1