From the one-day work absences during the past year, the personnel director for a large firm has identified the day of week for a random sample of 150 of the absences. Given the following observed frequencies, and if we are to conclude that one-day absences during the various days of the week are not equally likelyat 0.01 level of significance, what is the degree of freedom? Monday Tuesday Wednesday Thursday Friday Total 42 18 24 27 39 150

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-12 -5(x + 4) = 3x

-12 - 5x - 20 = 3x

-12 - 20 - 5x = 3x

-32 - 5x = 3x

    + 5x   + 5x

-32 = 8x

8         8

- 4= x

step-by-step explanation:

we have

using a graphing tool

see the attached figure

this is a quadratic equation (vertical parabola) open up

the vertex is a > vertex

the domain of the function is all real > interval (-∞,∞)

the range of the function is the > [-6.125,∞)

the function has two x->   and

the function is increasing over the > (0.25,∞)

the function is decreasing over the > (-∞,0.25)

the answer for the question that you are asking is 4

the answer is 15 to your question