A punter kicks a football. Its height, h(t), in metres, t seconds after the kick is given by the equationh (t)=−4.9t2+18.24t+0.8. The height of an approaching blocker’s hands is modelled by the equationg (t)=−1.43t+4.26, using the same t. Can the blocker knock down the punt.
Please show full solution

Yes

Step-by-step explanation:

−4.9t² + 18.24t + 0.8 = −1.43t + 4.26

-4.9t² + 19.67t - 3.46 = 0

4.9t² - 19.67t + 3.46 = 0

Using quadratic formula:

t = [19.67 +/- sqrt(319.0929l)]/9.8

t = (19.67 +/- 17.8631716109)/9.8

t = 3.8299154705, 0.1843702438

Since the two can be at the same height at the same time, the blocker can knock down the punt

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)

5050 i think

step-by-step explanation: