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The answer to your question is 6.- B    7.- D

Step-by-step explanation:

Data

Parallelogram ACFG

6.-

m∠GAC = 112°

m∠ACF = ?

Process

These angles are supplementary, they measure the same.

                  ∠GAC + ∠ACF = 180

-Substitution

                      112 + ∠ACF = 180°

-Solve for ∠ACF

                      ∠ACF = 180° - 112°

-Result

                      ∠ACF = 68°

7.-

m∠AGF = 2a + 10

m∠ACF = a + 20

The angles ∠GAC and ACF are equal, they measure the same.

                   ∠GAC = ∠ACF

-Substitution

                   a + 20 = 2a + 10

-Solve for a

                   a - 2a = 10 - 20

-Result

                   -a = -10

                    a = 10

-Find ∠AGF

      ∠AGF = 2(10) + 10

                 20 + 10

                = 30°

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2