How do large shops estimate the cost of welding ?

1. a^4+8a^3+24a^2+32a+16

2.y^8+8y^7+28y^6+56y^5+70y^4+56y^3+28y^2+8y+1

3.x^6-3x^4y^2+3x^2y^4-y^6

i hope i can you

by the distributive property of all reals, we have that

p(n) = 2n^2(n^2 + 2n - 3)

by virtue of factoring, it is true that p(n) = 2n^2(n+3)(n-1).

should we want p(n) = 0, we know that at least one of 2, n^2, n+3, or n-1 needs to be zero by the zero factor property. 0 times anything is zero.

so the answer is n = 0, n = -3, and n = 1 as the roots because those are the values of n for which p(n) is 0.