4. You are given ∆, with vertices A(2, -3),B(5,4), and C(9,0). What are the new coordinates after reflecting ∆ over the x-axis? *

1. A(-2,-3), B(-5,4), C(-9,0)
2. A (2,3), B(5,-4), C(9,0)
3. A(-3,2), B(4,5), C(0,9)

5. You are given ∆, with vertices A(2, -3),B(5,4), and C(9,0). What are the new coordinates after reflecting ∆ over the y-axis? *

1, A(-2,-3), B(-5,4), C(-9,0)
2. A (2,3), B(5,-4), C(9,0)
3. A(-3,2), B(4,5), C(0,9)

6. You are given ∆, with vertices A(2, -3),B(5,4), and C(9,0). What are the new coordinates after reflecting ∆ over the line y=x? *

1. A(-3,2), B(4,5), C(0,9)
2. A(-2,-3), B(-5,4), C(-9,0)
3. A (2,3), B(5,-4), C(9,0)

4. 2. A (2,3), B(5,-4), C(9,0)

5. 1. A(-2,-3), B(-5,4), C(-9,0)

6. 1. A(-3,2), B(4,5), C(0,9)

Step-by-step explanation:

4. You are given ∆, with vertices A(2, -3),B(5,4), and C(9,0). What are the new coordinates after reflecting ∆ over the x-axis? *

2. A (2,3), B(5,-4), C(9,0)

(x , y) --> (x,-y)

5. You are given ∆, with vertices A(2, -3),B(5,4), and C(9,0). What are the new coordinates after reflecting ∆ over the y-axis? *

1, A(-2,-3), B(-5,4), C(-9,0)

(x , y) --> (-x,y)

6. You are given ∆, with vertices A(2, -3),B(5,4), and C(9,0). What are the new coordinates after reflecting ∆ over the line y=x? *

1. A(-3,2), B(4,5), C(0,9)

(x,y) --> (y,x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.