The length of the shadow of a pole on level ground increases by 90 metres when the angle of elevation of the sun changes from 58 degrees to 36 degrees. calculate and correct to three s. f , the height of the pole

120 m

Step-by-step explanation:

Let the length of the pole be a and the shadow be b at 58° and b+90 at 36°.

Then, as the pole and its shadow form a right triangle, we have:

As,

The equations change to:

Comparing the two equations:

Then

step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)

360/29

step-by-step explanation: