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Mathematics, 17.04.2020 16:47 judyd452

Which ratio can be used to solve for y in the triangle below?

sin75/25= sin40/y
sin40/25= sin75/y
sin25/75= siny/40
sin25/40= siny/75


Which ratio can be used to solve for y in the triangle below?sin75/25= sin40/ysin40/25= sin75/y sin2

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Which ratio can be used to solve for y in the triangle below?

sin75/25= sin40/y
sin4...
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