According to the Fundamental Theorem of Algebra, which polynomial function has exactly 11 roots? f (x) = (x minus 1) (x + 1) Superscript 11 f (x) = (x + 2) cubed (x squared minus 7 x + 3) Superscript 4 f (x) = (x Superscript 5 Baseline + 7 x + 14) Superscript 6 f (x) = 11 x Superscript 5 Baseline + 5 x + 25

yor answer is 7/6 times 5

step-by-step explanation:

step-by-step explanation:

the answer is the option b

the range is all real numbers

step-by-step explanation:

we know that

the absolute value parent function is equal to

see the attached figure to better understand the problem

so

a. it is v-shaped > is true

b. the range is all real numbers > is not true

because the range is the > [0,∞)

all real numbers greater than or equal to zero

c. it goes through the origin > is true

d. the domain is all real numbers > is true

step-by-step explanation:

step-by-step explanation:

first you will have to convert 3/4 into a decimal

which is .75

then you will have to divide 1.5 by .75

which is 2

no you have to divide