A company president randomly selects 5 employees to complete a survey. There are 50 employees in the company. In how many different ways can these employees be selected, if the order of selection does not matter?

254,251,200

Step-by-step explanation:

This is a combination question, since the order doesn't matter, the formula for combinations is n!/(n-r)! n is the amount of things we can choose from but r is the amount of things (employees in this case) we actually select. n = 50 and r = 5. This we get 50!/(50-5)! or 50!/45!, using a calculator, we can find that 50!/45! is equal to 254,251,200. That is our final answer for the amount of combinations available.