With a rate of change = 0.10 & an initial value = 10, how would you represent this as a linear equation?

y = 0.10x + 10, where m = 0.10 & b = 10

y = 10x + 0.10, where m = 10 & b = 0.10

y = .10x +10

Step-by-step explanation:

If the equation is linear, we can write it in the form y=mx+b where m is the slope and b is the y intercept

The y intercept is where we start, or the initial value

The slope is also call the rate of change

y = .10x +10

First one

Step-by-step explanation:

rate of change = 0.10

Means

The slope = 0.10

m = 0.10

An initial value = 10

Means

y-intercept = 10

b = 10

y = mx + b

y = 0.10x + 10

the answer is 8

step-by-step explanation:

3.14 x 8x8

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0