A teacher wants to award prizes for 1st, 2nd, 3rd, 4th and 5th in the class of
30. In how many ways can the prizes be awarded (assume no two students
tie)?

2,052,086,400.

Step-by-step explanation:

Permutation

Pr = n! / (n-r)!

30P5 = 30! / (30-5)

30P5 = 30x29x28x27x26x25! / 25!

(Just cancel the 25! on the numerator and denominator for easier solving.)

30P5 = 30x29x28x27x26

30P5 = 17,100,720.It is not the final answer because we can still arrange the 5 winners.

5! = 5×4×3×2×1 = 12017,100,720 × 120 = 2,052,086,400

answer: c

because if you look at the chart you can see a pattern and compare it to the question he simplify out your

but i think the formula is f(x)=6x

55% are girls and 45% are boys : ) hope this

step-by-step explanation: