A box contains 2 red marbles, 3 green marbles, and 3 blue marbles.
If we choose a marble, then another marble without putting the first one back in the box, what is the
probability that the first marble will be green and the second will be blue?
How many

9/56

Step-by-step explanation:

the odds of the first one being green is 3/8

the odds of the second one being blue is 3/7 because one was removed

multiply these to find the probability

3/8*3/7=9/56

step-by-step explanation:

first you will have to convert 3/4 into a decimal

which is .75

then you will have to divide 1.5 by .75

which is 2

no you have to divide