One factor of x3 + 2x2 -x -2 is x+2 . Find two other factors of this polynomial.

x^3+2x^2-x-2=(x+2)(x-1)(x+1)

The other two factors are x-1 and x+1

Step-by-step explanation:

Use synthetic division:

x^3+2x^2-x-2 / x+2

-2 | 1 2 -1 -2

       -2 0 2

     1 0 -1 0

This means x^2-1 with no remainder, but we can still break it down. The factors of -1 are 1 and -1, so we must find the factors:

1 | 1 0 -1

      1  1

   1  1 0

This means x+1 so that's one factor

-1 | 1 0 -1

      -1  1

    1 -1 0

This means x-1 so that's the other factor

Thus, the factors of x^3+2x^2-x-2 are (x+2)(x+1)(x-1)

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3