Please Help! <3 What is the center and the radius of a circle with the following equation.

So the center is (0,-4) and the radius is 6

Step-by-step explanation:

We can write the equation of a circle as

(x-h)^2 + (y-k) ^2 = r^2  where (h,k) is the center and r is the radius

We have

(x)^2 + (y+4) ^2 = 36

(x-0)^2 + (y- -4) ^2 = 6^2

So the center is (0,-4) and the radius is 6

Centre: (0,-4)

Radius: 6

Step-by-step explanation:

(x - h)² + (y - k)² = r²

(x - 0)² + (y - (-4))² = 6²

Centre: (0,-4)

Radius: 6

the equation of the parallel line would be y = 2x + 9

step-by-step explanation:

to start we need to find the slope of the original line. we can do that by looking at the coefficient of x, which is 2

since the slope of the original line is 2 and parallel lines have the same slope, we know the new line will also have 2 slope. now we can use that along with the point given in point-slope form to get the find equation.

y - y1 = m(x - x1)

y - 5 = 2(x + 2)

y - 5 = 2x + 4

y = 2x + 9