A 11 gram sample of substance that's used to treat thyroid disorders s has a k-value of 0.1247

You don't have a question but I'll answer what I can.

half-life = natural log (.5) / k

half-life =  -.693147 / .1247

half-life = 5.561106656

It seems you did not express the k-value properly.

1) A k-value should have a negative value.

2) A k-value should also have units.

For example, the k-value of tungsten 181 is

-0.005723757 / days

Step-by-step explanation:

0.5 days.

Step-by-step explanation:

Assuming N is final mass at half life

Not sure if correct. Please see attached.

the answer is 844

step-by-step explanation:

it is 844 because if you add 836.50 + 7.5 you will get 844

b: |12 – x| ≤ 0.25

step-by-step explanation:      

let x be the possible lengths in inches, of the ribbons jaime cut.

we have been given that jaime is cutting strips of ribbon for a project. he tries to cut each piece to be 12 inches long, but sometimes he cuts it too long or too short by as much as 0.25 inch.  

we can represent this information in an inequality as:

by the definition of absolute value function we will get,

upon combining our inequalities we will get,

therefore, the inequality   describes all the possible lengths (x), in inches, of the ribbons jaime cut.

step-by-step explanation: