At a local zoo, the number of resident birds is twice the number of four-legged mammals. If the total number of legs between the birds and mammals equals 80, how many birds are there?

Step-by-step explanation:

Total number of legs = 80

So if there are 10 mammals so there legs = 40

And the no of resident birds should be twice

So there are 20 resident birds and number of legs = 20 × 2 = 40

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step-by-step explanation:

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there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1