This is for algebra 2 if you know this please help! Thank you. Offering lots of points for BOTH questions (:

1) first number is -3 and 2nd number is 6.

Step-by-step explanation: equations are 5x+2y=-3 and 3x+3y=9

first start by trying to get either the x or y to the same number but 1 is negative and 1 is positive.

-3(5x+2y=-3) = -15x-6y=9

5(3x+3y=9) = 15x+15y=45

now cross out -15x and 15x so you're left with -6y=9 and 15y=45. Now combine like terms. You should get 9y=54. Now solve normally. Y=6.

Plug it into the first equation and solve.

5x+2(6)=-3    

5x+12=-3    

(subtract the 12 from both sides) 5x=-15

x=-3

QUESTION 2

first number is 7 and 2nd is 4

Step-by-step explanation: equations are 3x-6y=-3 and 2x+4y=30

first start by trying to get either the x or y to the same number but 1 is negative and 1 is positive.

2(3x-6y=-3) = 6x-12y=-6

3(2x+4y=30) = 6x+12y=90

now cross out-12x and 12x so you're left with 6x=-6 and 6x=90. Now combine like terms. You should get 12x=84. the answer is x=7

Plug it into the first equation and solve.

3(7)-6y=-3    

-6y+21=-3

Now add -21 to both sides of the equation

-6y=-24

y=4

$9.89

step-by-step explanation:

9.90 = p x .06 x .25 (3/12 changed to a decimal)

9.90 = p x 0.015

9.90 - 0.015 = p

9.89 = p