The function E(d)=0.25d√ approximates the number of seconds it takes a dropped object to fall d feet on Earth. The function J(d)=0.64⋅E(d) approximates the number of seconds it takes a dropped object to fall d feet on Jupiter. How long (in seconds) does it take a dropped object to fall 50 feet on Jupiter? Round your answer to the nearest hundredth.

1.13 seconds

Step-by-step explanation:

step 1

Find out how (in seconds) does it take a dropped object to fall 50 feet on Earth

we have

we have

substitute

step 2

Find out how (in seconds) does it take a dropped object to fall 50 feet on Jupiter

we have

For

Remember that

substitute

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

let's solve your equation step-by-step.

24−3x=−27

step 1: simplify both sides of the equation.

24−3x=−27

24+−3x=−27

−3x+24=−27

step 2: subtract 24 from both sides.

−3x+24−24=−27−24

−3x=−51

step 3: divide both sides by -3.

−3x

−3

=

−51

−3

x=17

answer:

x=17

step-by-step explanation:

mark brainliest and have a great day!