Limit as x approaches pi/2 of cos(x)/x-(pi/2)

 plug in x=0 gives 0/0. This is one of the indeterminate forms (some others are ∞/∞ and 0·∞) use L'Hospital's Rule. 
Differentiate the top and bottom of the fraction: 
lim (cos x) / (x - π/2) => lim (-sin x) / (1 - 0) 
Now you can substitute x = π/2 without problem 
lim = -1/1= -1

Weiiejjrjfjjffjffkdkdod