What is the solution to the rational equation 4 over 3 plus the fraction 2 over x plus 5 equals negative 6 over 3x plus 15

5 over x+2 PLUS 6 over x-2 EQUALS 14 over x-1 How do I solve this equation!? 5/(x + 2) + 6/(x - 2) = 14/(x - 1) tranfer "5/(x + 2) + 6/(x - 2)" to the other side & change the sign 0 = 14/(x - 1) - 5/(x + 2) - 6/(x - 2) LCD = (x - 1) ;(x + 2) ; (x - 2) 0 = 14(x + 2)(x - 2) - 5(x - 1)(x - 2) - 6(x - 1) (x + 2) 0 = 14(x² - 4) - 5(x² - 3x + 2) - 6(x² + x - 2) 0 = 14x² - 56 - 5x² + 15x - 10 - 6x² - 6x + 12 combine terms 0 = 14x² - 5x² - 6x² + 15x - 6x - 56 - 10 + 12 0 = 3x² + 9x - 54 divide by 3 0/3 = 3x²/3 + 9x/3 - 54/3 0 = x² + 3x - 18 answer

The answer mai bc