A volume of a coin is 113.04 mm2 what is the approximate of a sphere that has the same height and a circular base with the same diameter?Use 3.14 for x round to the nearest hundredth

We have been given that the volume of a cone is 113.04 cubic mm. We are asked to find the approximate volume of a sphere that has the same height and a circular base with the same diameter.

We know that volume of cone is .

The height is equal to the diameter. We know that diameter is 2 times radius, so we can represent this information in an equation as:

Upon substituting in volume of cone, we will get:

We know that volume of sphere is .

Upon comparing volume of cone with volume of sphere, we can see that volume of sphere is 2 times the volume of cone.

Since , so volume of sphere would be:

Therefore, volume of sphere would be 226.08 cubic mm.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3