What additional information do you need to prove that ∆LMX ≅ ∆LOX by the HL Theorem?

LM = LO

Explanation: In order to use the HL Theorem the triangles included must be right triangles and in this case they must have a congruent hypotenuse and in order for that, LM must be congruent to LO.

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step-by-step explanation:

you have to round up to 4 because 6 is over 5 so you have to round the 3 up to 4