What are the possible numbers of positive, negative, and complex zeros of f(x) = −x6 − x5 − x4 − 4x3 − 12x2 + 12?

There is only one change of sign, so there is only one possible positive root.



There are five changes of signs, so there are 5,3 or 1 possible negative roots.

The number of complex roots can be equal to 4,2 or 0 (degree of a polynomial - possible positive roots - possible negative roots)

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