Choose one of the factors of 500x3 + 108y18
(500x to the 3rd + 108y to the 18th)

a. 25x2 + 15xy6 + 9y2
b. 5x + 3y6
c. all of the above
d. 6

Option C

Therefore, one of the factors of is .

Step-by-step explanation:

Given:

the common factor from and is 4.

therefore,

Now, use the formula for above expression:

here, and

Therefore, we have

Therefore, one of the factors of is .

The correct option is B.

Step-by-step explanation:

The given expression is

Take out 4 as a common factor.

Use the formula ,

Here and

The factors of given expression are 4, and .

Therefore only option B is correct.

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!

i think the answer is seven, for if i'm being useless °ω°

step-by-step explanation: