All else being equal, if you cut the sample size in half, how does this affect the margin of error when using the sample to make
a statistical inference about the mean of the normally distributed population from which it was drawn?
ME-205
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The margin of error is multiplied by V0.5
The margin of error is multiplied by 2
The margin of error is multiplied by 0.5.
The margin of error is multiplied by 2

this is the formula: v = the value of investment at the end of the time period

p = the principal amount (the initial amount invested)

r = the annual interest rate

n = the annual frequency of compounding (how many times a year interest is added)

t = the number of years the money is invested

^ means raise to the power of

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct

the equation is not included but the answer is (1.50, 2.00, 2.75)

step-by-step explanation:

idk

step-by-step explanation: