According to Ohm's Law, if the current of a copper wire is increased from 10 A to 20 A, what will the
resistance of that copper wire be if it is initially set at 12 Ohms and the voltage stays the same?
06 Ohms
3 Ohms
12 Ohms
24 Ohms

3; 9 is 8 to -4

step-by-step explanation:

i think is g(1)=-1.

hope that i can

the answer would be 1 1/72

step-by-step explanation:

you can rewrite the equation by separating the parts and then solving individually:

10-9=1

1/8 - 1/9=

find l c d and then combine:

1 1/72

hope this is what you were asking for!

step-by-step explanation: