Drag and drop a statement or reason to each box to complete the proof. Given: parallelogram EFGH Prove: EG¯¯¯¯¯ bisects HF¯¯¯¯¯¯ and HF¯¯¯¯¯¯ bisects EG¯¯¯¯¯ . Parallelogram E F G H with diagonals E G and H F intersecting at point K. Statement Reason parallelogram EFGH Given EF¯¯¯¯¯∥HG¯¯¯¯¯¯ When two parallel lines are cut by a transversal, alternate interior angles are congruent. The opposite sides of a parallelogram are congruent. △EKF≅△GKH ASA Congruence Postulate CPCTC EG¯¯¯¯¯ bisects HF¯¯¯¯¯¯ and HF¯¯¯¯¯¯ bisects EG¯¯¯¯¯ .

The question is incomplete. The complete question has been added as an attachment to the solution.

To aid easy identification of the unknowns, I attached another document where I numbered the unknowns.

1) EF ≅ HG

2) EF || HG

3) <FEK ≅ <HGK

<EFK ≅ <GHK

4) When two parallel lines are cut by a transversal, alternate interior angles are congruent.

5) EK ≅ GK

FK ≅ HK

Step-by-step explanation:

1) In the given parallelogram EFGH,

It is stated that the opposite sides of a parallelogram are congruent. Therefore, EF ≅ HG

2) It would be noted from the properties of a parallelogram, that the opposite sides are parallel. Therefore, EF || HG

3) Definition of a parallelogram: A parallelogram is a quadrilateral with two opposite sides that are parallel and equal in length.

4) One of the properties of a parallelogram states that when two parallel lines are cut by a transversal, alternate interior angles are congruent.

5) It can be seen from the question that △EKF≅△GKH as a result of congruence Postulate.

And the CPCTC proves,

EK ≅ GK

FK ≅ HK

CPCTC means Corresponding Parts of Congruent Triangles are Congruent.

When you have two triangles that have been proven as congruent, then each part of one triangle is equal in size and shape to the corresponding part in the other triangle.

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

i think it is everything has to equal 180 so, if i correct 4=c. 6=d. 8=a. 7=b. and the last question would be c. because they are parallel lines and they are congruent.

step-by-step explanation:

the reason everything has to equal to 180 is because that is how it works. i'm guessing that is its rule. 4 and 8 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 6 and 7 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 60+60 is 180. so, now you have your answer