The ball's height( in meters above the ground), x seconds after Amir threw it, is modeled by : h(x)=-(x-2)^2 +16 what is the height of the ball at the time its thrown?

20 m

Step-by-step explanation:

The height of the ball in metres is given as:

where xis time, in seconds.

At the instant that the ball is thrown, the time is 0 seconds. This means that the height will be h(0):

The height of the ball is 20 metres.

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a