Which of the following is NOT true when testing a claim about a proportion? Choose the correct answer below. A. Both the traditional method and P-value method use the same standard deviation based on the claimed proportion p, but the confidence interval uses an estimated standard deviation based on the sample proportion ModifyingAbove p with caretp. B. When testing claims about population proportions, the traditional method and the P-value method are equivalent in the sense that they always yield the same result. C. A conclusion based on a confidence interval estimate will be the same as a conclusion based on a hypothesis test. D. If you want to test a claim about population proportions, use the P-value method or the classical method of hypothesis testing.

C. A conclusion based on a confidence interval estimate will be the same as a conclusion based on a hypothesis test.

Explanation: The One-Sample Proportion Test is used to assess whether a population proportion (P1) is significantly different from a hypothesized value (P0). This procedure calculates sample size and statistical power for testing a single proportion using either the exact test or other approximate z-tests.

To write a null hypothesis, first, start by asking a question. Rephrase that question in a form that assumes no relationship between the variables. In other words, assume a treatment has no effect. Write your hypothesis in a way that reflects this.

A null hypothesis is a hypothesis that says there is no statistical significance between the two variables. It is usually the hypothesis a researcher or experimenter will try to disprove or discredit. An alternative hypothesis is one that states there is a statistically significant relationship between two variables.

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.