There are 5 packages in a room. The masses of the packages are in whole numbers. If each package has a different mass, and the average mass of the package is 16 kg, what is the heaviest that a package could be?

Hint: The lightest package could be is 1 kg

step-by-step explanation:

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

answer is 144

step-by-step explanation:

1/800 is the right answer