A standard deck of cards has 52 cards divided into 4 suits, each of which has 13 cards. Two of the suits ($\heartsuit$ and $\diamondsuit$, called 'hearts' and 'diamonds') are red, the other two ($\spadesuit$ and $\clubsuit$, called 'spades' and 'clubs') are black. The cards in the deck are placed in random order (usually by a process called 'shuffling'). In how many ways can we pick two different cards

The number of ways to select 2 cards from 52 cards without replacement is 1326.

The number of ways to select 2 cards from 52 cards in case the order is important is 2652.

Step-by-step explanation:

Combinations is a mathematical procedure to compute the number of ways in which k items can be selected from n different items without replacement and  irrespective of the order.

Permutation is a mathematical procedure to determine the number of arrangements of k items from n different items respective of the order of arrangement.

In this case we need to select two different cards from a pack of 52 cards.

Compute the number of ways to select 2 cards from 52 cards without replacement as follows:

Thus, the number of ways to select 2 cards from 52 cards without replacement is 1326.

Compute the number of ways to select 2 cards from 52 cards in case the order is important as follows:

Thus, the number of ways to select 2 cards from 52 cards in case the order is important is 2652.

i think it is everything has to equal 180 so, if i correct 4=c. 6=d. 8=a. 7=b. and the last question would be c. because they are parallel lines and they are congruent.

step-by-step explanation:

the reason everything has to equal to 180 is because that is how it works. i'm guessing that is its rule. 4 and 8 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 6 and 7 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 60+60 is 180. so, now you have your answer

do your own work and don"t cheat.

step-by-step explanation: