The weight distribution of parcels sent in a certain manner is normal with mean of 12 lb and standard deviation of 3 lb. The parcel service wishes to establish a weight value c beyond which there will be a surcharge. What value of c is such that 99% of all parcels are under the surcharge weight?

21.16

Step-by-step explanation:

Starting from the theory we have the following equation:

Using the data supplied in the exercise, we have subtracting the mean and dividing by the standard deviation:

solving for "c", knowing that fi is a tabulating value:

therefore the value of c is equal to 21.16

lol

step-by-step explanation:

it is a. 4.2 because 7.6-3.4 gets the remaining length of 4.2. i might be wrong but i am pretty sure this is the answer.