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Mathematics, 21.04.2020 17:13 67bryant

OA



OC

start overline, O, A, end overline, \perp, start overline, O, C, end overline

\qquad m \angle AOB = 6x - 12^\circm∠AOB=6x−12



m, angle, A, O, B, equals, 6, x, minus, 12, degrees

\qquad m \angle BOC = 3x + 30^\circm∠BOC=3x+30



m, angle, B, O, C, equals, 3, x, plus, 30, degrees

Find m\angle AOBm∠AOBm, angle, A, O, B:


OA ⊥ OC start overline, O, A, end overline, \perp, start overline, O, C, end overline\qquad m \angle

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