Suppose Julio is a veterinarian who is doing research into the weight of domestic cats in his city. He collects information on 131 cats and finds the mean weight for cats in his sample is 10.87 lb with a standard deviation of 4.31 lb. What is the estimate of the standard error of the mean (SE)

Estimate of the standard error of the mean = 0.38 lb

Step-by-step explanation:

We are given the following in the question:

Sample mean, = 10.87 lb

Sample size, n = 131

Standard deviation, σ = 4.31 lb

We have ti find the estimate of the standard error of the mean.

Formula for standard error:

Putting values, we get,

0.38 lb is the standard error of the mean.

answer: 140

step-by-step explanation:

so just add all then it will be your answer but i am not pretty sur eif it is but hope this i am here to people

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240