Consider this right triangle with the squares of the two legs given.

3 squares are positioned to form a right triangle. The small square is labeled 36, medium square is 64, and large square is not labeled.

The side length of the largest square is the hypotenuse of the right triangle.

Which is the area of the largest square?

Which is the length of the hypotenuse?

1, 100

2, 10

Step-by-step explanation: I just did it

what do you need me to answer?

step-by-step explanation:

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?