Determine whether the Mean Value theorem can be applied to f on the closed interval [a, b]. (Select all that apply.) f(x) = 3x3, [1, 2] Yes, the Mean Value Theorem can be applied. No, because f is not continuous on the closed interval [a, b]. No, because f is not differentiable in the open interval (a, b). None of the above. If the Mean Value Theorem can be applied, find all values of c in the open interval (a, b) such that f '(c) = f(b) − f(a) b − a . (Enter your answers as a comma-separated list. If the Mean Value Theorem cannot be applied, enter NA.) c = 27

Yes, the Mean Value Theorem can be applied.

The value of c is c=1.5275

Step-by-step explanation:

The mean value theorem states that for a given two endpoints of an interval and a continuos function f, there is at least one point within this interval at which the tangent to the function f (first derivative) is parallel to the secant of the endpoints of the interval.

For the function f(x) and the interval:

the condition of continuity is met, so the mean value theorem can be applied.

To calculate the value c such that:

we have to calculate the first derivative of f(x)

Now we calculate the secant slope:

Now we can write:

spinning a 1, 2, or 3. option d.

step-by-step explanation: when spinning a number graph up to 4, and aiming for any number less than 3, that automatically eliminates the number 4. now you have two numbers to spin on that are less than 3, but the number 3 is included in this question because it's no greater of an number than itself. i hope this you : )