Find the area of a rectangle that has a length of (x - 5) and a width of (3x + 1).

A=3x^2 -14x -5

Step-by-step explanation:

(x-5)(3x+1)

3x^2 +x -15x -5

3x^2 -14x -5

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

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step-by-step explanation: