The weight distribution of parcels sent in a certain manner is normal with meanvalue 12 pounds and standard deviation 3.5 pounds. The parcel service wishes to establish aweight valuecbeyond which there will be a surcharge. What value ofcis such that 99% ofall parcels are under the surcharge weight?

The parcel with weight less than 20.14 pounds are 99% of all parcels under the surcharge weight.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 12 pounds

Standard Deviation, σ = 3.5 pounds

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

We have to find the value of x such that the probability is 0.99

Calculation the value from standard normal z table, we have,  

Thus, parcel with weight less than 20.14 pounds are 99% of all parcels under the surcharge weight.

9.55 degrees.

step-by-step explanation:

the given angle is

1 cycle is equal to 2π radians. so 4π will be equal to two cycles.

5.166667π-4π = 1.166667π

hence, this angle goes a little more than negative x axis.

1.166667π-π= 0.166667π

hence, the reference angle is 0.166667π radians.

1 radian = 57.2958 degrees

now, in degrees, this should be equals to 9.55 degrees.

for the free

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