Connor went to a carnival with 22.50$. He bought a hot dog and a drink for $3.75 and he wanted to spend the rest of his money on ride tickets which cost $1.25 each. What is the maximum number of ride tickets that he can buy

The maximum number of ride tickets that he can buy is; 15

Connor has 22.50$, bought a hot dog and a drink for $3.75.

In essence, the amount Connor has left is;

= $18.75

Therefore, if he wanted to spend the rest of his money on ride tickets which cost $1.25 each, the maximum number of ride tickets that he can buy can be evaluated as follows;

No. of ride tickets = $18.75/$1.25

No. of ride tickets = 15

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15

Step-by-step explanation:

22.50-3.75=18.75

18.75/1.25=15

BRAINLIEST WOULD BE APPERCIATED

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.